Question

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At a certain height a shell at rest explodes into two equal fragments. One of the fragments receives horizontal velocity u. The time time interval after which, the velocity vectors will be inclined at 120° to each other is



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Answer 1

Answer:

Since there is no external force in horizontal direction, momentum is conserved.

Taking right horizontal direction as positive x-axis and downward direction as y-axis.

Therefore the second fragment will have the same speed but in opposite direction.

Taking

$(v1)x = ui \: cap \:$

$(v2)x = - ui \: cap$

total velocity at time t

$v1bar = uicap \: + gtjcap \:$

$v2bar = - uicap + gtjcap$

$\frac{v1bar.v2bar}{ |v1| |v2| } = \cos(120)$

${ - u}^{2} + ({gt})^{2} = - \frac{1}{2} ({u}^{2} + ( {gt})^{2} )$

$t = \frac{u}{ \sqrt{3}g }$

Explanation:

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