answer fast......................If nth term of an A.P. is 4, common difference is 2 and sum of n terms is –14, then find first term and the number of terms.
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sn =n/2(2a + (n-1)d)
-14 =4/2(2a(4-1)3)
-14-2 =2a+6
-16 -6=2a
2a=-22
a=-11
an =a+(n-1)d
an= -11+(4-1)2
= -11+6
an = -5
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