Question

Answer fast!!!! If u r a champion them solve.

Answer 1

let "t" = time after which both stones meet

"S" = distance travelled by the stone dropped from the top of tower

(100-S) = distance travelled by the projected stone.


◆ i) For stone dropped from the top of tower

-S = 0 + 1/2 (-10) t²

or, S = 5t²


◆ ii) For stone projected upward

(100 - S) = 25t + 1/2 (-10) t²

= 25t - 5t²


Adding i) and ii) , We get

100 = 25t

or t = 4 s


Therefore, Two stones will meet after 4 s.


◆ ¡¡¡) Put value of t = 4 s in Equation i) , we get 

S = 5 × 16 

= 80 m.


Thus , both the stone will meet at a distance of 80 m from the top of tower.

hope this helps you...:)