Question

Answer fast in easy steps

Answer 1

Let us join AC and PQ

ΔACQ and ΔAQP are on the same base AQ and between the same parallels AQ and
CP.
Area (ΔACQ) = Area (ΔAPQ)
Area (ΔACQ) − Area (ΔABQ) = Area (ΔAPQ) − Area (ΔABQ)
Area (ΔABC) = Area (ΔQBP) (i)
Since AC and PQ are diagonals of parallelograms ABCD and PBQR respectively,
Area (ΔABC) =  Area (ABCD) (ii)
Area (ΔQBP) =  Area (PBQR) (iii)
From equations (i), (ii), and (iii), we obtain
 Area (ABCD) =  Area (PBQR)
Area (ABCD) = Area (PBQR)