Question

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Answer 1

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$log_{ \sqrt{2} }(256) + log_{ \sqrt{2} }(64)$

as ,

$\longrightarrow$log x + log y = log xy

so, here ,

$\implies \: log_{ \sqrt{2} }(256 \times 64) \\ \\ \implies \: log_{ \sqrt{2} }( {2}^{8} \times {2}^{6} ) \\ \\ \implies log_{ \sqrt{2} }( {2}^{14} )$

as ,

$\longrightarrow$ log xⁿ = n log x

$\implies \: 14 \: log_{ \sqrt{2} }(2) \\ \\ \implies \: 14 \: log_{ \sqrt{2} }( {( \sqrt{2} )}^{2} ) \\ \\ \implies \: 14 \times 2 log_{ \sqrt{2} }( \sqrt{2} ) \\ \\ \implies \: 28$

It means ,

$\implies \: 28 = 27 + 1 = {3}^{3} + 1$

Option 3 is correct

{r u in 11th ?}

Answer 2

Step-by-step explanation:

answer is 3.....

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hope it helps you