Question

answer fast l will mark as branliest​

Answer 1

Answer:

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Answer 2

i) ∆BMD ~= ∆CND

angleM = angleN. ( each 90°)

BD = CD. ( d is midpoint)

angle DBM = angle DCN ( alternate angle)

by SAS ∆BMD~= ∆CND

BM = CN ( by CPCT)

hence , proved

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