Question

Answer Fast....
Let A = {2, 3, 4, 5, 6, 7, 8, 9} let R be the relation on A defined by {(x, y) : x, y ∈ A, x is a multiple of y and

x ≠ }. Find the relation.​

Answer 1

Step-by-step explanation:

Here, x R y if x divides y, therefore,

(i) R={(2,2),(2,4),(2,6),(2,8),(3,3),(3,6),(3,9),(4,4),(4,8),(5,5),(6,6),(7,7),(8,8),(9,9)} 

(ii) Domain of R ={2,3,4,5,6,7,8,9}=A

(iii) Range of R ={2,3,4,5,6,7,8,9}=A

(iv) R−1=(y,x):(x,y) in R=(2,2),(4,2),(6,2),(8,2),(3,3),(6,3),(9,3),(4,4),(4,8),(5,5),(6,6),(7,7),(8,8),(9,9)

Infact R−1 is {(y,x):x,y∈A,y is divisible by x}

(a) As (2,2),(3,3),(4,4),(5,5),(6,6),(7,7),(8,8) and (9,9) belong to R, therefore, R reflexive.

(b) Here, R is not symmetric. We may observe the (2,4)∈R but (4,2)∈/R. Infact, 'x' divides 'y' does not imply 'y divides x' when x=y.

(c) As 'x' divides y' and 'y divides z' imply 'x divides z'. the therefore, the relation R is transitive.

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Answer 2

Hi I will help you ✌️

=> R = { (2,2) , (2,4) , (2,6) , (2,8) , (3,3) , (3,6) , (3,9) , (4,4) , (4,8) , (5,5) , (6,6) , (7,7) , (8,8) , (9,9) } .