Question

answer fast. need it fast​

Answer 1

Answer:

m= -5 & n = 6

Step-by-step explanation:

Given equation : $3x^{2} -5x+6=0$

$=> 3x^{2} -3x-2x+6=0$

$=>3x(x-1)-2(x-1)=0$

$=>(3x-2)(x-1)=0$

$=> x = \frac{2}{3} , 1$

$=> 3x = 2,3$

Equation:

$x^{2} -(\alpha +\beta )x+\alpha \beta =0$ , α = 2, β = 3

$=> x^2-(2+3)x-(2)(3)=0$

Therefore the equation is $x^{2} -5x+6=0$

On comparing with $x^{2} +mx+n=0$ m = -5 & n = 6

Answer 2

Answer:

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