Science, asked by Anonymous, 1 year ago

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Answered by Anonymous
2
1) We All Know

Work Done = Force * Displacement

We have Work Done = 75 J

Force = 10 N

Displacement = Work Done/Force

= 75/10

= 7.5 m


2) Work Done = Potential Energy

Potential Energy = Mass*Height*g

Mass = 50 kg

Height = 72 m

g = 9.8

Work Done = 50*72*9.8

= 35,280 J

= 35.28 Kilo J


3) Kinetic Energy = 1/2*Mass*(Velocity²)

Mass = 2kg

Velocity = 0.1 m/s

Kinetic Energy = 1/2*2*0.1²

= 0.1²

= 0.01 J


4) Potential Energy = Mass*Height*g

Mass = 10 kg

Height = 50 m

g = 9.8

Potential Energy = 10*50*9.8

= 4900 J

= 4.9 Kilo J

So It is Freely Falling Under Gravity

Initial Velocity = 0 m/s

Acceleration = g or 9.8 m/s

Height = 50 m

V² = U² + 2gH

V = √2gH

Kinetic Energy = 1/2*Mass*Velocity ²

= 1/2*M*2gH

= 10*9.8*50

= 4.9 Kilo J


5) Kinetic Energy = 1/2*Mass*Velocity²

K = 1/2*m*u²

K" = 1/2*m*(2u)²

K/K" = (1/2*m*u²)/(1/2*m*4u²)

K/K" = u²/4u²

K/K" = 1/4

K:K" = 1:4

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Answered by Anonymous
1

1. Work Done = Force * Displacement

We have Work Done = 75 J

Force = 10 N

Displacement = Work Done/Force

= 75/10

= 7.5 m

2) Work Done = Potential Energy

Potential Energy = Mass*Height*g

Mass = 50 kg

Height = 72 m

g = 9.8

Work Done = 50*72*9.8

= 35,280 J

= 35.28 Kilo J

3) Kinetic Energy = 1/2*Mass*(Velocity²)

Mass = 2kg

Velocity = 0.1 m/s

Kinetic Energy = 1/2*2*0.1²

= 0.1²

= 0.01 J

4) Potential Energy = Mass*Height*g

Mass = 10 kg

Height = 50 m

g = 9.8

Potential Energy = 10*50*9.8

= 4900 J

= 4.9 Kilo J

So It is Freely Falling Under Gravity

Initial Velocity = 0 m/s

Acceleration = g or 9.8 m/s

Height = 50 m

V² = U² + 2gH

V = √2gH

Kinetic Energy = 1/2*Mass*Velocity ²

= 1/2*M*2gH

= 10*9.8*50

= 4.9 Kilo J

5) Kinetic Energy = 1/2*Mass*Velocity²

K = 1/2*m*u²

K" = 1/2*m*(2u)²

K/K" = (1/2*m*u²)/(1/2*m*4u²)

K/K" = u²/4u²

K/K" = 1/4

K:K" = 1:4

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