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answer 3.
cost of one table = x
cost of one chair = y
acc. to first condition
2x + 3y = 2000 ...........(1)
for second condition
3x +2y = 2500 ...............(2)
now solving (1) and (2)
multiply ........(1) by 3 and ....(2) by 2
we get,
6x + 9y = 6000 after multiplying .(1)
6x + 4y = 5000 after multiplying .(2)
- - -
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0x + 5y = 1000
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so we get
5y =1000
y = 1000/5 = 200
so the price of one chair = 200
putting this value in equation ....(1)
2x +3(200) = 2000
2x + 600 =2000
2x = 2000-600
2x =1400
x =1400/2 =700
so cost of one table is 700
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we have to find
x + 5y
700 +5(200) =700 + 1000 =1700
hence the total cost of one table and five chair is rs. 1700
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hope it helps u
(3)
Let, the cost of one table be Rs. x and that of one chair is Rs. y
By the given conditions,
- 2x + 3y = 2000 .....(i)
- 3x + 2y = 2500 .....(ii)
Multiplying (i) by 3 and (ii) by 2, we get
- 6x + 9y = 6000
- 6x + 4y = 5000
On subtraction, we get
5y = 1000
⇒ y = 200
Putting y = 200 in (i), we get
2x + 3 (200) = 2000
⇒ 2x + 600 = 2000
⇒ 2x = 2000 - 600 = 1400
⇒ x = 700
So, cost of one table is Rs. 700
and cost of one chair is Rs. 200
Thus, cost of 5 chairs is
= Rs. (5 × 200) = Rs. 1000
Therefore, total cost of 1 table and 5 chairs is
= Rs. (700 + 1000) = Rs. 1700
(4)
Let, cost of a pen is Rs. x and that of a pencil is Rs. y
By the given conditions,
- 59x + 47y = 513 .....(i)
- 47x + 59y = 441 .....(ii)
From (i), we get
59x = 513 - 47y
⇒ x = (513 - 47y)/59 .....(iii)
Substituting x = (513 - 47y)/59 in (ii), we get
47 (513 - 47y)/59 + 59y = 441
⇒ (47 × 513) - (47 × 47)y + (59 × 59)y = 441 × 59
⇒ 24111 - 2209y + 3481y = 26019
⇒ 1272y = 1908
⇒ y = 1.5
Putting y = 1.5 in (iii), we get
x = {513 - (47 × 1.5)}/59
⇒ x = (513 - 70.5)/59
⇒ x = 7.5
Therefore, the cost of a pen is Rs. 7.50 and that of a pencil is Rs. 1.50