Math, asked by Anonymous, 11 months ago

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Answered by Swarup1998
10

(5)

Let, the two numbers be x and y (x > y)

By the given conditions,

  • x - y = 26 .....(i)
  • x = 3y .....(ii)

Substituting x = 3y in (i) no. equation, we get

3y - y = 26

⇒ 2y = 26

⇒ y = 13

From (ii), we get

x = 3 (13)

⇒ x = 39

Therefore, the two numbers are 39 and 13

(6)

Let, the present age of father is x years and that of son is y years

By the given conditions,

  • x = 3y + 3 .....(i)
  • x + 3 = 2 (y + 3) + 10 .....(ii)

Putting x = 3y + 3 in (ii) no. equation, we get

3y + 3 + 3 = 2y + 6 + 10

⇒ 3y + 6 = 2y + 16

⇒ 3y - 2y = 16 - 6

⇒ y = 10

Putting y = 10 in (i) no. equation, we will get

x = 3 (10) + 3

⇒ x = 30 + 3

⇒ x = 33

Therefore, the present age of father is 33 years and that of son is 10 years

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