Question

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Answer 1

Answer:

average of the smallest 5 odd numbers in the given set = 7

Step-by-step explanation:

let the 10 consecutive odd numbers be

2n-9,2n-7,2n-5,2n-3,2n-1,2n+1,2n+3,2n+5,2n+7,2n+9

given than average = 120

=> (2n-9+2n-7+2n-5+2n-3+2n-1+2n+1+2n+3+2n+5+2n+7+2n+9)/10 = 120

=> 10*2n = 120

=> n = 120/20

=> n = 6

=> the smallest 5 numbers among the given odd numbers will be 2(6)-9,2(6)-7,2(6)-5,2(6)-3,2(6)-1

=> the smallest 5 numbers among the given odd numbers will be 12-9,12-7,12-5,12-3,12-1

=> the smallest 5 numbers among the given odd numbers will be 3,5,7,9,11

=> average of the smallest 5 odd numbers in the given set = (3+5+7+9+11)/5

=> average = 35/5 = 7