Question

answer fast please

10th standard question

it's urgent​

Answer 1

$\huge\mathfrak\red {answer:-}$

$p(x) = 4 {x}^{2} - (8 {k}^{2} - 40k)x - 9$

$let \: one \: zero \: be \: \alpha \: and \: the \: other \: be \: - \alpha$

$\alpha + ( - \alpha ) = \frac{ - b}{a}$

$\alpha - \alpha = \frac{8 {k}^{2} - 40k}{4}$

$0 = \frac{8 {k}^{2} - 40k}{4}$

$8 {k}^{2} - 40k = 0$

divide by 8k

$k - 5 = 0$

$k = 5$

$<marquee>mark me as brainliest.</marquee>$