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Answers
Answer:
9.6 m
Step-by-step explanation:
Let R, S and M represent the position of Reshma, Salma and Mandeep respectively.
Draw perpendicular OL on RS.
As OL ⊥ RS,
OL^2 = OR^2 - RL^2
=> OL^2 = 5^2 - 3^2
=> OL^2 = 25 - 9
=> OL^2 = 16
=> OL = 4
Now we know,
Area of triangle = 1/2 * B * H
Area ΔORS = 1/2 * KR * OS = 1/2 * KR * 5 ---- (1)
Also,
Area ΔORS = 1/2 * OL* RS = 1/2 * 4 * 6 = 12 ---- (2)
Solve (1) and (2).
=> 1/2 * KR * 5 = 12
=> KR = 24/5
=> KR = 4.8 m
As the perpendicular from the centre of a circle bisects the chord.
RM = 2KR
RM = 2 * 4.8
RM = 9.6 m
Result :
Distance between Reshma and Mandip = 9.6 m.
#Hope my answer helped you.
Step-by-step explanation:
Answer:
9.6 m
Step-by-step explanation:
Let R, S and M represent the position of Reshma, Salma and Mandeep respectively.
Draw perpendicular OL on RS.
As OL ⊥ RS,
OL^2 = OR^2 - RL^2
=> OL^2 = 5^2 - 3^2
=> OL^2 = 25 - 9
=> OL^2 = 16
=> OL = 4
Now we know,
Area of triangle = 1/2 * B * H
Area ΔORS = 1/2 * KR * OS = 1/2 * KR * 5 ---- (1)
Also,
Area ΔORS = 1/2 * OL* RS = 1/2 * 4 * 6 = 12 ---- (2)
Solve (1) and (2).
=> 1/2 * KR * 5 = 12
=> KR = 24/5
=> KR = 4.8 m
As the perpendicular from the centre of a circle bisects the chord.
RM = 2KR
RM = 2 * 4.8
RM = 9.6 m
Result :
Distance between Reshma and Mandip = 9.6 m.