Question

answer fast please..




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Answer 1

Answer:

cant see ur question

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Answer 2

Answer:

in ∆BLC and ∆CMB

angle MBC = angle LCB (since AC = AB)

angle MCB = angle LBC (bisectors of equal angles)

BC = CB (common)

hence ∆BLC is congruent to ∆ CMB

so BL = CM