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Answer:
Step-by-step explanation:
=1/3y^2-4/7y+5-2/7y+2/3y^2-2-1/7y+3-2y^2
=y^2(1/3+2/3-2)-y/7(4+2+1)+5-2+3
=-y^2-y+6
=-(y^2+y-6)
=-(y^2+3y-2y-6)
=[y(y+3)-2(y+3)]
=(y+3)(y-2)
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Answered by
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Answer:
(y+3)(y-2)..............follow
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