Question

answer fast please .........​

Answer 1

$\huge\mathfrak{Question⇒}$

$Subtract\:the\:sum\:of\:\frac{5}{6},\:\frac{7}{8}\:and\:\frac{11}{12}\:from\\the\:sum\:of\:2\frac{4}{5},\:1\frac{3}{10}\:and\:3\frac{1}{15.}$

$\huge\mathfrak{To\:find⇒}$

$The\:difference.$

$\huge\mathfrak{Solution⇒}$

$(2\frac{4}{5}+1\frac{3}{10} +3\frac{1}{15} )-(\frac{5}{6}+\frac{7}{8} +\frac{11}{12})$

$\tiny\mathtt{Convert\:all\:mixed\:fractions\:into\:improper\:fractions.}$

$=(\frac{14}{5} +\frac{13}{10} +\frac{46}{15})-(\frac{5}{6}+\frac{7}{8} +\frac{11}{12} )$

$=[\frac{(84+39+92)}{30} ]-[\frac{(20+21+22)}{24} ]$

$=\frac{215}{30}-\frac{63}{24}$

$=\frac{43}{6} -\frac{21}{8}$

$=\frac{(172-63)}{24}$

$=\frac{109}{24}$

$=4\frac{13}{24}$

$\huge\mathfrak{Hence⇒}$

$(2\frac{4}{5} +1\frac{3}{10} +3\frac{1}{15})-(\frac{5}{6}+\frac{7}{8} +\frac{11}{12} )=4\frac{13}{24}$

$\huge\mathfrak{Therefore⇒}$

$On\:subtracting\:the\:sum\:of\:\frac{5}{6},\:\frac{7}{8}\:and\:\frac{11}{12}\\from\:the\:sum\:of\:2\frac{4}{5},\:1\frac{3}{10}\:and\:3\frac{1}{15},\\we\:get\:4\frac{13}{24}.$

$\huge\mathfrak{Final\:answer⇒}$

$4\frac{13}{24}$

$\huge\mathfrak{Done࿐}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

$\large\bold{\mathtt{Have\:a\:nice\:day.}}$