Question

Answer fast please!!!!!!!!​

Answer 1

Answer:

4. x=0

5.

(i)  The coordinates will be (0,4)

(ii) The coordinates will be (8,0)

Explanation:

4.

To find zeroes we equate the polynomial to 0,

so

p(x)= 0

$\\\tt (x-2)^2 - (x+2)^2 = 0 \\ \\\tt x^2 -4x + 4 -(x^2 + 4x +4) =0 \\ \\\tt -8x =0 \\\tt \implies x = 0$

5.

For the values on x axis we set x= 0

and for values on y axis we set y = 0

x+2y=8

i) 0 + 2y = 8,

⇒ y= 4

The coordinates will be (0,4)

ii) x + 2(0) =8

⇒ x= 8

The coordinates will be (8,0)