Question

answer fast please;
(4cosec²2theta + 4cosec²2theta cot²2theta)sin⁴2theta

i will.mark brainlest for whoever gives correct answer with proper steps!
​

Answer 1

Step-by-step explanation:

$(4 {cosec}^{2} x \: + 4 {cosec}^{2} x \times {cot}^{2} x) {sin}^{4} x \\ = \frac{4}{ {sin}^{2}x } \times { \sin }^{4} x + 4 \times \frac{1}{ {sin}^{2}x } \times \frac{ {cos}^{2}x }{ {sin}^{2} x} \times {sin}^{4} x \\ = 4 {sin}^{2} x \: + 4 \: {cos}^{2} x \\ = 4( {sin}^{2} x + {cos}^{2} x) \\ = 4 \times 1 \\ = 4 \: ans$

I have taken" x" instead of" theta".

Answer 2

Answer:

Plzz plzz follow me and mark me as brainliest and thnk all my answers ❤❤❤