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it's simple
given question
N = √(√5+2) + √(√5-2) /√(√5+1) - √(3-2√2)
squaring both sides
N^2 =
√(√5+2)^2 + √(√5 -2)^2 +2√( √5+2)(√5-2) /√ (√5+1) ^2- √(3-2√2)^2
formula used : (a+b) ^2 = a^2+b^2 +2ab
= √5+2+√5-2+2(√ (√5) ^2 - 2^2) / √5+1 - 3-2√2
= 2√5 + 2(√(5-4) ) /√5+1 - 3-2√2
= 2√5 + 2√1 / √5+1 - 3-2√2 (√1 = 1)
= 2(√5+1) /√5+1 - 3-2√2
= 2 - (3-2√2)
= -1-2√2
= 2√2- 1
now N^2 = 2√2 -1
N = (2√2-1) ^1/2
= √(2√2 -1)
putting value of √2 = 1.414
we get
N = √(2*1.414 - 1)
= √( 2.828 -1 )
= √1.828
= 1.352 (answer)
please recheck it, if wrong please correct me. Best method for u my friend, enjoy.
hope u understood it
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