Question

answer fast please chapter name powers​ last 4

Answer 1

Answer:

3 Expressing as a rational number

1 - 5 to power -1

answer - 1/5 to the power 1 that is 1/5

3- (-3/5) to the power -3

answer - 5 /3 to the power 3 that is 125 /27

2 , 4 do in the same way

5 - (-5)-1 ×1 /5 to the power -1

then it will become

1/5 to the power 1 × 5 to the power 1

powers as same multiply 1/5×5

answer is 1

7 - you will get 8 /3 to the power 3 ÷ 16 /3 to the power 3

you will get

512 /27 ÷ 4096 /27

512/27 ×27 /4096

cross multiply

answer is 1/8

8 - 1 /3 -1/4 to the power -1

lcm 12

you will get

1 /12 to the power -1

answer is 12

10 - base are same equate the power

you will get 2 /7 to the power -1

answer is 7/2

if munis is the there replace the numerator and denominator and uses formula.

you can solve other problems

Answer 2

Answer (i) :

${5}^{ - 1}$

$\frac{1}{5}$

Answer (ii) :

${( - 6)}^{ - 2}$

${( \frac{1}{6} )}^{2}$

$\frac{1}{36}$

Answer (iii) :

${( \frac{ - 3}{5} )}^{ - 3}$

${( \frac{5}{ - 3} )}^{ 3}$

$\frac{125}{ - 27}$

$\frac{ - 125}{27}$

Answer (iv) :

${( \frac{ - 1}{2} )}^{ - 5}$

${( \frac{2}{ - 1} )}^{5}$

$\frac{32}{ - 1}$

Answer (v) :

${( - 5)}^{ - 1} \times {( \frac{1}{5} )}^{ -1}$

$\frac{1}{ - 5} \times \frac{5}{1}$

$\frac{1}{ - 1} \times \frac{1}{1}$

$\frac{1}{ - 1}$

Answer (vi) :

$({ \frac{3}{7}) }^{ - 1} \times {( \frac{7}{3} )}^{ - 1}$

$\frac{7}{3} \times \frac{3}{7}$

$\frac{1}{1} \times \frac{1}{1}$

$1$

Answer (vii) :

${ (\frac{3}{8}) }^{ - 3} \div { (\frac{3}{16} )}^{ - 3}$

$({ \frac{8}{3}) }^{3} \div ({ \frac{16}{3} )}^{3}$

$\frac{512}{27} \times \frac{27}{4096}$

$\frac{1}{1} \times \frac{1}{8}$

$\frac{1}{8}$

Answer (viii) :

$({ {3}^{ - 1} - {4}^{ - 1}) }^{ - 1}$

${ ( \frac{1}{3} - \frac{1}{4} ) }^{ - 1}$

$\frac{3}{1} - \frac{4}{1}$

$1$

Answer (ix) :

$({ \frac{4}{9} )}^{ - 2} \times \ ({ \frac{3}{2}) }^{ - 3}$

${( \frac{9}{4}) }^{2} \times {( \frac{2}{3}) }^{3}$

$\frac{81}{16} \times \frac{8}{27}$

$\frac{3}{2} \times \frac{1}{1}$

$\frac{3}{2}$

Answer (x) :

${( \frac{2}{7} )}^{2} \times {( \frac{2}{7}) }^{ - 3}$

$\frac{4}{49} \times {( \frac{7}{2}) }^{3}$

$\frac{4}{49} \times \frac{343}{8}$

$\frac{1}{1} \times \frac{7}{2}$

$\frac{7}{2}$

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