Math, asked by lal420053, 1 month ago

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Answered by mohit32416
0

Step-by-step explanation:

let \: the \: age \: of \: the \: son \: be \: x \: and \: \\ age \: of \: his \: father \: be \:  30 + x \\ so \: 30 + x + 12 = 3(x + 12) \\  = 42 + x = 3x + 36 \\  = 42 - 36 = 3x - x \\  = 6 = 2x \\ x =  \frac{6}{2}  \\ x = 3

so the age of son is 3 yrs and his fathers age is 30+3=33 yrs

Answered by Muskan402255
0

Answer:

let be the present age of the son be 'x' years

the the father's age will be (x+30) years

after 12years

father's age= x+42

son's age = x+ 12

by given condition

3(x+12)=x+42

3x+36=x+42

2x=6

x=3

the present age of the son is 3 years and the present age of the father is 3+30= 33 years

Step-by-step explanation:

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