Question

Answer fast please it's urgent​

Answer 1

Let the angles be a,b,c,d

a:b:c:d=1:2:3:4

Given a+b+c+d=360

$\frac{a}{1} = \frac{b}{2} = \frac{c}{3} = \frac{d}{4} = k$

a=k,b=2k,c=3k,d=4k

a+b+c+d=10k=360

k=36

a=36;b=72;c=108;d=144

$if \: \frac{a}{b} = \frac{5}{7} \rightarrow \: 1$

$\frac{b}{c} = \frac{14}{15} \rightarrow \: 2$

1×2

$\frac{a}{b} \times \frac{b}{c} = \frac{5}{7} \times \frac{14}{15}$

$\frac{a}{b} = \frac{2}{3}$