Question

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Answer 1

$\underline{\underline{To Find:}}$

• The profit or loss percentage, if the object is sold at ₹675 .

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$\underline{\underline{Given:}}$

$loss\% = 6\%$

$S·P = s_{1} = 564$

$S·P = s_{2} = 675$

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$\underline{\underline{Taken:}}$

let the C·P be x.....

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$\underline{\underline{We\:Know:}}$

$profit = S·P - C·P$

$loss = C·P - S·P$

$P\% = \bigg(\dfrac{P}{C·P} × 100\bigg)\%$

$L\% = \bigg(\dfrac{L}{C·P} × 100\bigg)\%$

$S·P = \bigg(1 - \dfrac{P}{100} of C·P\bigg)$

$S·P = \bigg(1 - \dfrac{L}{100} of C·P\bigg)$

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$\underline{\underline{Concept:}}$

For Finding the profit or loss percentage , when the pair of jeans is sold at ₹675 , first we have to find out the C·P of the pair of jeans.

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$\large\underline{\underline{Solution:}}$

• $\underline{To\:Find\:the\:C·P\:of\:the\:pair\:of\:jeans:}$

Using the formula ,

☞ $S·P = \bigg(1 - \dfrac{L}{100} of C·P\bigg)$

$\Rightarrow 564 = \bigg(1 - \dfrac{6}{100} of x\bigg)$

$\Rightarrow 564 = \bigg(\dfrac{100 - 6}{100} of x\bigg)$

$\Rightarrow 564 = \bigg(\dfrac{94}{100} of x\bigg)$

$\Rightarrow 564 = \bigg(\dfrac{94x}{100}\bigg)$

$\Rightarrow 56400 = 94x$

$\Rightarrow \dfrac{56400}{94} = x$

$\Rightarrow 600 = x$

${\boxed{\therefore C·P = R.s 600}}$

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• $\text{To find the profit or loss percentage when the selling price is 675}$

Since the S·P is greater than the C·P it is a profit.

we know ,

$\therefore profit = S·P - C·P$

$\Rightarrow P = 675 - 600$

$\Rightarrow P = 75$

${\boxed{\therefore P = 75}}$

$\underline{\underline{Profit\:percentage:}}$

we know;

$\therefore P\% = \bigg(\dfrac{P}{C·P} × 100\bigg)\%$

$\Rightarrow P\% = \bigg(\dfrac{74}{600} × 100\bigg)\%$

$\Rightarrow P\% = \bigg(\dfrac{74}{6}\bigg)\%$

$\Rightarrow P\% = \bigg(\dfrac{37}{3}\bigg)\%$

$\Rightarrow P\% = 12.3(Approx.)\%$

${\boxed{\therefore P\% = 12.3\%}}$