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Answered by llMichFabulousll
56

Explanation:

(x)=(x−2)² −(x−2)²

This is in the form of a²-b²

P(x)=(x−2+x+2)(x−2−(x+2))

P(x)=2x(x−2−x−2)

P(x)=2x(−4)

P(x)=0

−8x=0

x=0

Hence,

x=0 is the zero of the polynomial P(x)

5((i) We know that the point which lies on x-axis has its ordinate 0.

So, putting y=0 we get:

x+2×0=8⇒x=8

hence, (8,0) lies on the x-axis

(ii) We know that the point which lies on y-axis has its abscissa 0.

So, putting x=0 we get:

0+2y=8⇒2y=8⇒y=4

hence, (0,4) lies on the y-axis

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Answered by BrainlyJossh
7

Answer:

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Correct answer is upar.

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