Math, asked by jashansidhu8757, 9 months ago

answer fast please very important ​

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Answered by Anonymous
1

Step-by-step explanation:

3x+y =1

(2k-1)x+(k-1)y-2k-1=0

solution =

condition a1/a2= b1/b2not equal to c1/c2.

a1/a2= 3/ (2k-1) = b1/b2= 1/ (k-1) not equal to c1/c2= -1/(2k -1)

...

3/2k-1 = 1/k-1

3(k-1) =1(k-1)

3k-3=2k-1

3k-3-2k+1

3k-2-2k

k=2

..hope it helps you

Answered by Anonymous
1

Answer:

k = two your answer..,.,.,,.,,.,.

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