answer fast please very important
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Answered by
1
Step-by-step explanation:
3x+y =1
(2k-1)x+(k-1)y-2k-1=0
solution =
condition a1/a2= b1/b2not equal to c1/c2.
a1/a2= 3/ (2k-1) = b1/b2= 1/ (k-1) not equal to c1/c2= -1/(2k -1)
...
3/2k-1 = 1/k-1
3(k-1) =1(k-1)
3k-3=2k-1
3k-3-2k+1
3k-2-2k
k=2
..hope it helps you
Answered by
1
Answer:
k = two your answer..,.,.,,.,,.,.
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