Question

answer fast please
What is the solution of y = e^600x​

Answer 1

We have to find ordered pairs (x, y) such that LHS = RHS

$\\y=e^{600x}\\Taking\:log\:on\:both\:sides\\\implies log(|y|) =log(|e^{600x}|)\\\implies log(|y|)=600x\\\implies x =\frac{log(|y|)}{600}$

∴The solution is

$\{(x,y)|\:x=\frac{log(|y|)}{600},\:y\in \mathbb{R}\}$

Answer 2

The solution is of the given expression becomes,

{(x,y) l x}= log(y)÷600

Step-by-step explanation:

Given expression:

y=$e^{600x}$

Simplifying the above expression:

y=$e^{600x}$

Taking log on both sides:

log(y)=log($e^{600x}$)

Since

Log$e^{x}$= x

Using this:

logy= 600x

The value of x becomes,

x= log y÷600

Result:

Thus the solution is of the given expression becomes,

{(x,y) l x}= log(y)÷600

(#SPJ3)