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In the square ABCD,
- AB = 20 cm,
- E is the mid point of BC,
∴ BE = ½(BC) = ½(20 cm) = 10 cm
We know,
Pythagoras theorem:
c² = a² + b²
[relation b/w hypotenuse and base, height of a right triangles.]
∴ in △ABE,
(AE)² = (AB)² + (BE)²
⟹ (AE)² = (20)² + (10)² = 400 + 100 = 500
⟹ AE = √500 = 22.36... cm.
∴ The answer will be 22.3 cm.
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