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Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\large{\underbrace{\bf{\red{Required\:Solution:}}}}$

Here, we have to simplify the following :

$\displaystyle{\sf{(2^{4} \times 2^{5}) ÷ (2^{2} \times 2^{3})}}$

To simplify this, firstly we need to know some of the law of exponents :

• Law 1 - $\displaystyle{\sf{a^{m} \times a^{n} = a^{m+n}}}$
• Law 2 - $\displaystyle{\sf{ \dfrac{a^{m}}{a^{n}} = a^{m-n}}}$

So now let's simplify this!

$\implies{\sf{(2^{4} \times 2^{5}) ÷ (2^{2} \times 2^{3})}}$

• we have added the exponents of the same base by following law1.

$\implies{\sf{(2^{4+5}) ÷ (2^{2+3})}}$

• Now we've to subtract the exponent of the Numerator from the exponent of denominator by following law2.

$\implies{\sf{\dfrac{(2^{9})}{(2^{5})}}}$

• simplifing this.

$\implies{\sf{ 2^{9-5}}}$

$\large{\boxed{\sf{\orange{ 2^{4} = 16}}}}$

Therefore, the answer is b) 16.

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