Math, asked by sunilchandrasekharam, 5 months ago

Answer fast plus and no wrong answers​

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Answered by manya7734
1

Answer:

Indices (1 61/64) ^ (- 2/3) (2a ^ - 3 * b ^ 2) ^ 3 (a ^ - 1 + b ^ - 1)/((ab) ^ - 1) (x ^ - 1 * y ^ - 1)/(x ^ - 1 + y ^ - 1) ((4 * 10 ^ 7)(6 * 10 ^ - 5))/(8 * 10 ^ 10) (3a)/(b ^ - 1) + (2b)/(a ^ - 1) 5 ^ 0 * 4 ^ - 1 + 8 ^ (1/3) (0 * 027) ^ (- 1/3) (^ -1 / 27 )^ -2/3 (8/125) ^ (- 1/3) (1) @ 10

Answered by itzyadu
2

Answer:

da.. ninte veed evide..

eath clasila

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