Question

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a hemispherical bowl is made of steel has inner diameter 10.5 cm find the cost of tin plating it on inside at the rate of rupees 16 per 100 cm square​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given,

Diameter ( d ) = 10.5 cm

1 cm² = 16 rupees

To find : CSA ( hemisphere ) = ?

d = 10.5 cm

r = d / 2

= 10.5 / 2

= 105 / 20

= 52.5 / 10

r = 5.25 cm

CSA ( Hemisphere ) = 2 π r²

= 2 × ( 22 / 7 ) × 5.25 × 5.25

CSA ( Hemisphere ) = 173.25 cm²

1 cm² = 16 rupees

173.25 cm² = 16 × 173.25

173.25 cm² = 2772 rupees