Question

Answer fast plz.. if I get the rgt answer I will mark as brainliest ​

Answer 1

Required Answer:-

We have a circle with some lines intersecting each other internally. AOD is a straight line. That means,

⇒ ∠AOC + ∠COD = 180°

⇒ ∠AOC + 130° = 180°

⇒ ∠AOC = 50°

Considering O to be the centre, we know that the angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle. Then,

⇒ 2∠ABC = ∠AOC

And we know the measure of ∠AOC and ∠ABC is denoted as x here. Hence,

⇒ 2x = 50°

⇒ x = 25°

$\therefore$ The required value of x or ∠ABC:

$\huge{ \boxed{ \sf{ \purple{25 \degree}}}}$

Answer 2

$\: \: \: \: \:{\large{\bold{\sf{\underbrace{Understanding \: the \: question}}}}}$

☞ This question says that there is figure given of circle and this question ask us to find the value of x in given circle. 4 points are given as A, B, C and D. Some lines are drawn too. They are intersecting each other. Here AOD form a straight line. Point O is centre point and measure 130° Am by seeming this we get it how to do this question let's see.

$\: \: \: \: \:{\large{\bold{\sf{\underline{Full \: solution}}}}}$

☞ <AOC + <COD = 180° ( Linear Pair )

☞ <AOC + 130° = 180°

☞ <AOC = 180° - 130° ( - = + ; + = - )

☞ <AOC = 50°

$\rule{300}{2}$

☞ 2<ABC = <AOC

☞ 2x = 50° ( Given and Finded )

☞ x = 50° / 2

☞ x = 25°

• Henceforth, the measurement of x is 25°

$\: \: \: \: \:{\large{\bold{\sf{\underbrace{More \: information}}}}}$

Diagram of circle :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large x\ cm}\end{picture}$

Circle related :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\qbezier(1.6,-1.6)(1.6,-1.6)(1.6,1.6)\qbezier (-1.6,-1.6)(-1.6,-1.6)(-1.6,1.6)\qbezier (-1.6,-1.6)(-1.6,-1.6)(1.6,-1.6)\qbezier (-1.6,1.6)(-1.6,1.6)(1.6,1.6)\put (-2.1,1.8){\sf A}\put (1.8,1.75){\sf B}\put (1.9,-2){\sf C}\put (-2.1,-2.05){\sf D}\qbezier (-1.6,1.6)(-1.6,1.6)(1.6,-1.6)\put (0,0){\circle*{0.15}}\put (0.15,0.1){\bf O}\end{picture}$

Circle with diameter :

$\setlength{\unitlength}{1mm}\begin{picture}(50,55)\linethickness{0.4mm}\qbezier(45,30)(45,30)(5,30)\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\multiput(5,30)(20,0){3}{\circle*{1}}\end{picture}$

Request :

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