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in the following figure abc is a triangle and PQ//BC, show that angle A +angle b+ angle c=180°
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let angle PAB=1
angle QAC=2
PAB+QAC+BAC=180° (l.p.).......1
angle PAB=angle ABC (adjacent angle).........2
angle QAC=angle ACB ". ". .......3
from eq. 1,2,3
ABC+BCA+ACB=180°
hence proved
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