Question

ANSWER FAST PLZ IT IS VERY HARD

Answer 1

Answer:

A=P(1+R1/100)*(1+R2/100)

A=12000(1+5/100)*(1+6/100)

A=12000*1113/1000

A=13356

So,CI=A-P

CI=13356-12000=1356.(ans)

Answer 2

Answer:

Amount after 2 years = ₹13,356

Compound Interest after 2 years = ₹1356

• Refer to the attachment for step-by-step solution.

______...

When the interest is compounded annually but rates are different for different years,

we use this formula,

${\bf{\boxed {\purple { A = P \times [( 1 + \frac{p}{100}) \times (1 + \frac{q}{100})] }}}}$

Where,

• P = principal

• p = p.a during 1st year

• q = p.a during second year

___________......

Additional Information-

Few important formulae related to compound interest -

When the interest is compounded annually -

$\huge\rm\green { A = ₹P ( 1 + \frac{R}{100}{}^{n})}$

• Here, n years is the time.

______....

When the interest is compounded half- yearly -

$\huge\rm\green {A = ₹P(1 + \frac{R}{2 \times 100} ) {}^{2n}}$

________...

When the interest is compounded quarterly -

$\huge\rm\green {A = ₹P(1 + \frac{R}{4 \times 100} ) {}^{4n}}$