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Answer 1

In ΔCEF,

CE = 10 cm and EF = 6cm

Using Pythagoras theorem:

⇒CE² = CF² + EF²

⇒CF²= CE² – EF²

⇒CF² = 152 – 62

⇒CF² = 225-36

⇒CF² = 189

⇒CF = √189

= √ (9×21) = 3√21 cm

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From the figure we can write,

Area of trapezium = Area of parallelogram AECD +

Area of area of triangle CEF

Area of trapezium = height + 1/2 (sum of parallel sides)

Area of trapezium = 3√21 × 1/2 (25 + 13) Area of trapezium = 3√21 × 19 = 57√21

∴ Area of trapezium = 57√21 cm²

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I hope it helps.

Answer 2

Answer:

Hi LAKSHYA , its me PRIYANI your school friend