Physics, asked by srivastavhena, 8 months ago

answer fast ..
the correct answer will surely get the brainliest marking...otherwise nonsense will be reported...​

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Answered by nathuls202058
0

Answer:

Distance travelled by the space craft in t=10s

= Distance travelled in first 6s+ distance travelled in next 4s

Distance travelled in first 6 seconds: s1=ut+1/2 at  

2

 

Distance travelled in the next 4 seconds :s2=ut+1/2 at  

2

 

s1=ut+1/2 at  

2

 

=(75)(6)+1/2(7.5)(6)  

2

 

=450+135

=585 km

At the end of 6 seconds, the speed is 120 km/s

Distance covered in the next 4s−s2= speed × time

S2=120×4=480 km

∴ the distance covered by the aircraft in 10s=s1+s2=585 km+480 km=1065 km.

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