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The quadratic polynomial whose sum of zeros is 8 and product of zero is - 56 is
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Let the zeros of the quadratic equation be alpha and beta. As we know the product of the zeroes of a quadratic equation is equal to c/a and sum is equal to -b/a. Hence c = -56 and a = 1 and b = -1 from the above.
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x^2-8x-56 = 0
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