answer fast this ques
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LHS= (Cosec@+ 1/cot@) ²
=(cosec@-1)²/cot²@
=(cosec@-1) (cosec@+1) /cosec²@-1
=(cosec@-1) (cosec@+1) /(cosec@-1) (cosec@-1)
=cosec@+1/cosec@-1
hence LHS = RHS
Step-by-step explanation:
PLEASE note the use of @ instead of theta
formula used: a²-b² = (a-b) (a+b)
cot²@= cosec²@-1
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