Question

answer fast urgent.​

Answer 1

Given-

AB=60cm

GH=40cm

Let CD=EF=x cm

Average=45cm

Then,

$\frac{60 + 40 + x + x}{4} = \: 45$

$\frac{100 + 2x}{4} = \: 45$

$100 + 2x = 45 \times 4$

$100 + 2x = 180$

$2x = 180 - 100$

$2x = 80$

$x = \frac{80}{2} => x = 40$

Therefore, CD=EF=40cm

Midpoint of AB= 60/2=30cm

Midpoint of GH= 40/2=20cm

Midpoint of CD and EF= 40/2=20cm

Answer 2

Answer:

Step-by-step explanation:

Given-

AB=60cm

GH=40cm

Let CD=EF=x cm

Average=45cm

Then,

\frac{60 + 40 + x + x}{4} = \: 45

\frac{100 + 2x}{4} = \: 45

100 + 2x = 45 \times 4

100 + 2x = 180

2x = 180 - 100

2x = 80

x = \frac{80}{2} => x = 40

Therefore, CD=EF=40cm

Midpoint of AB= 60/2=30cm

Midpoint of GH= 40/2=20cm

Midpoint of CD and EF= 40/2=20cm