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Answers
Step-by-step explanation:
Solutions:-
Q-1:-
The sum of 3x²+4x-2 and -2x²+2x+1
=> (3x²+4x-2) + (-2x²+2x+1)
=> 3x²+4x-2-2x²+2x+1
=> (3x²-2x²)+(4x+2x)+(-2+1)
=> x²+6x-1
And
The sum of 6x²-4x+5 and -x²+15x+2
=> (6x²-4x+5)+( -x²+15x+2)
=> 6x²-4x+5-x²+15x+2
=> (6x²-x²)+(-4x+15x)+(5+2)
=> 5x²+11x+7
On subtracting 5x²+11x+7 from x²+6x-1
=> (x²+6x-1) - (5x²+11x+7)
=> x²+6x-1 -5x²-11x-7
=> (x²-5x²)+(6x-11x)+(-1-7)
=> -4x²-5x-8
Q-2:-
Given that
a = -2
b = -3
c = -4
The value of a²+b²-c
=> (-2)²+(-3)²-(-4)
=> 4+9+4
=> 17
Q-3:-
Given that
P = 3x+y-z
Q = 15x+4y-8z
R = 5x-y+8z
Now,
P+Q-R
=> (3x+y-z)+(15x+4y-8z)-(5x-y+8z)
=> 3x+y-z + 15x+4y-8z-5x+y-8z
=> (3x+15x-5x) +(y+4y+y)+(-z-8z-8z)
=> 13x+6y-17z
Q-4:-
Given that
(9x³-7x²-5)-(-2x³+4x²+1)+(6x³-5)
=> 9x³-7x²-5+2x³-4x²-1+6x³-5
=> (9x³+2x³+6x³)+(-7x²-4x²)+(-5-1-5)
=> 17x³-11x²-11
Q-5:-
The amount of Amar = 11x²+10x-4 rupees
Money spent by him = 6x²+4x-6 rupees
Remaining money
= (11x²+10x-4)-(6x²+4x-6)
=> 11x²+10x-4-6x²-4x+6
=> (11x²-6x²)+(10x-4x)+(-4+6)
=> 5x²+6x+2 rupees
The money is left with Amar = 5x²+6x+2 rupees
Answer:
i dont know no.1 but i wrote others answers
