Question

answer fast with proper steps​

Answer 1

answer:

join ac ,

now consider ∆le ABC,

< B+ < BAC + < BCA = 180°

50+ (<BAD + < DAC ) + (<BCD + <DCA ) = 180°

30 + < DAC + 55 + <DCA = 130°

→ <DAC + < DCA = 450 ° ----------> 1

consider ∆le <DAC ,

<DAC + < DCA + < ADC = 180° (from 1)

<ADC = 135°.

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Answer 2

Answer:

Buddy y u post one question a number of times...???