Question

Answer fast with propersteps
1. Find the square root of 4.6225 using division method:
2. The length of a rectangle is 3x² +5x-1 and its width is 3x + 1. Find its perimeter.​

Answer 1

Answer:

1 = 2.15

Step-by-step explanation:

I don't know second one so sorry

Answer 2

$\large\underline{\sf{Solution-1}}$

$\red{\rm :\longmapsto\: \sqrt{4.6225}}$

So, using Long Division Method, we have

$\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\:2.15 \:\:}}}\\ {\underline{\sf{2}}}& {\sf{\:\:4.6225 \:\:}} \\{\sf{}}& \underline{\sf{\:\:4 \:  \:  \: \: \: \: \:\:}} \\ {\underline{\sf{41}}}& {\sf{\:\:062 \:  \:  \: \:}} \\{\sf{}}& \underline{\sf{\:\:41 \:  \: \:}} \\ {\underline{\sf{425}}}& {\sf{\:\: \: \: 2125 \:\:}} \\{\sf{}}& \underline{\sf{\:\: \: \: 2125\:\:}} \\ {\underline{\sf{}}}& {\sf{\: \:   \:0\:\:}}{\sf{}}&{\sf{\:\:\:\:}}\end{array}\end{gathered}\end{gathered}\end{gathered}$

Therefore,

$\red{\rm :\longmapsto\: \sqrt{4.6225} = 2.15}$

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$\green{\large\underline{\sf{Solution-2}}}$

Given that,

$\red{\rm :\longmapsto\:Length_{(rectangle)} = {3x}^{2} + 5x - 1 \: }$

$\red{\rm :\longmapsto\:Breadth_{(rectangle)} = 3x + 1}$

We know that,

$\boxed{\tt{ Perimeter_{(rectangle)} = 2[Length_{(rectangle)} + Breadth_{(rectangle)}]}}$

So, on substituting the values, we get

$\rm :\longmapsto\:Perimeter_{(rectangle)} = 2({3x}^{2} + 5x - 1 + 3x + 1)$

$\rm :\longmapsto\:Perimeter_{(rectangle)} = 2({3x}^{2} + 8x)$

$\rm :\longmapsto\:Perimeter_{(rectangle)} = {6x}^{2} + 16x$

$\bf :\longmapsto\:Perimeter_{(rectangle)} = 2x(3x + 8)$

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Additional Information :-

$\boxed{\tt{ Perimeter_{(square)} = 4 \times side \: }}$

$\boxed{\tt{ Perimeter_{(circle)} = 2\pi \: r \: }}$

$\boxed{\tt{ Perimeter_{(rhombus)} = 4 \times side \: }}$

$\boxed{\tt{ Area_{rectangle} = Length \times Breadth \: }}$

$\boxed{\tt{ Area_{square} = {(side)}^{2} \: }}$