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Sn = 5n^2 +3n
=> n[2a +(n-1)d] /2 = n(5n + 3)
=> 2a +(n-1)d = 10n + 6
=> 2a +(n-1)d = 6+10n
=> 2a +(n-1)d = 16 - 10 +10n
=> 2a +(n-1)d = 16 - 10(n-1)
Comparing both sides, we get
d= - 10
a= 8
Tn = a +(n-1)d
Tn = 8 +(n-1)(-10)
Tn = 8 - 10n +10
Tn = 18 - 10n
Hope it will help you
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=> n[2a +(n-1)d] /2 = n(5n + 3)
=> 2a +(n-1)d = 10n + 6
=> 2a +(n-1)d = 6+10n
=> 2a +(n-1)d = 16 - 10 +10n
=> 2a +(n-1)d = 16 - 10(n-1)
Comparing both sides, we get
d= - 10
a= 8
Tn = a +(n-1)d
Tn = 8 +(n-1)(-10)
Tn = 8 - 10n +10
Tn = 18 - 10n
Hope it will help you
Please mark as brainliest if you liked the solution
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