Question

answer fastpls its from maths and

Answer 1

Tana  + 2Tan2a + 4Tan4a + 8Cot8a  = Cota

Step-by-step explanation:

replacing θ  with a  for easy writing

Tana  + 2Tan2a + 4Tan4a + 8Cot8a  = Cota

Concept used Tana + 2Cot2a = Cota

how :

Tana + 2Cot2a

= Tana   + 2/Tan2a

we knwo Tan2a = 2Tana /(1 - Tan²a)

= Tana  + 2(1 - Tan²a)/2Tana

= Tana  +  (1 - Tan²a)/Tana

= (Tan²a  + 1 - Tan²a)/Tana

= 1/Tana

= Cota

LHS

= Tana  + 2Tan2a + 4Tan4a + 8Cot8a

= Tana + 2Tan2a + 4(Tan4a + 2Cot8a )

= Tana + 2Tan2a + 4Cot4a

= Tana + 2(Tan2a + 2Cot4a)

= Tana  + 2Cot2a

= Cota

= RHS

Tana  + 2Tan2a + 4Tan4a + 8Cot8a  = Cota

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