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Find the product
(i) (a+7)×(a²+3a+)
(ii)(a + b + c)(a-b-c)
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(a+7) * (a^2+3a+5)
First multiply (a^2+3a+5) by a and then by 7. And add them.
(a^3+3a^2+5a)+(7a^2+21a+35)
a^3+10a^2+26a+35
→ (a + b - c) (a - b - c)
→ a(a - b - c) +b(a - b - c) -c(a - b - c)
→ a² - ab - ac + ab - b² - bc - ac + bc + c²
→ a² - b² + c² - ab + ab - bc + bc - ac - ac
→ a² - b² + c² - 2ac
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Answer:
→ (a + b - c) (a - b - c)
→ a(a - b - c) +b(a - b - c) -c(a - b - c)
→ a² - ab - ac + ab - b² - bc - ac + bc + c²
→ a² - b² + c² - ab + ab - bc + bc - ac - ac
→ a² - b² + c² - 2ac
Step-by-step explanation:
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