Question

answer for 10 question!!

Answer 1

Given sinA = 3/5.

We know that cos^2A = 1 - sin^2A

                                      = 1 - (3/5)^2

                                      = 1 - 9/25

                                      = 16/25

cosA = -(4/5).[since A is an obtuse angle].


Now,

Given sinB = (5/13)

= > cos^2B = 1 - sin^2B

                   = 1 - (5/13)^2

                   = 1 - 25/169

                   = 144/169


cos B = 12/13.

Given that A + B + C = 180

= > C = 180 - (A + B)

= > Sin c = sin(180 - (A + B))

= > Sin c = sin(A + B)

= > Sin c = sinAcosB + cosAsinB

                = (3/5)(12/13) + (-4/5)(5/13)

                = 36/65 - 20/65

                = 16/65.



Therefore, the value of sinC = 16/65 - Option(A)



Hope this helps!