answer for 11th question
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If ,then find the value of 4+cot∅.
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cos∅ = 1/√2
→ cos∅ = cos45°[cos45° = 1/√2]
→ ∅ = 45°
Now,
4+cot∅
→4 + cot45°
→4 + 1 [ cot45°=1]
→ 5 ( Answer)
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cos(theta) = 1/√2
cos(theta) = 45° [cos 45° = 1/√2]
(theta) = 45°
Now,
4 + cot(theta)
4 + cot 45°
4 + 1 [cot 45° = 1]
5
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