Answer for 5 and 6?’
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Normality = gram equivalent/vol.
volume = gram equivalent/normality
= 1/(1/10) = 10 L = 10000 cc
2)equivalent conductance = specific conductance × 1000/N
= 1000/R/( C)
= 1000/RC
volume = gram equivalent/normality
= 1/(1/10) = 10 L = 10000 cc
2)equivalent conductance = specific conductance × 1000/N
= 1000/R/( C)
= 1000/RC
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