Question

Answer for 50 points​

Answer 1

✅✅ANSWER BELOW ✅✅

R.E.F image 

R.E.F image l=5m,w=3.5m

R.E.F image l=5m,w=3.5mvolume of pit =14m3

R.E.F image l=5m,w=3.5mvolume of pit =14m3volume =l×b×h

R.E.F image l=5m,w=3.5mvolume of pit =14m3volume =l×b×h14=5×3.5×h

R.E.F image l=5m,w=3.5mvolume of pit =14m3volume =l×b×h14=5×3.5×h∴h=5×3.514=0.8m 

R.E.F image l=5m,w=3.5mvolume of pit =14m3volume =l×b×h14=5×3.5×h∴h=5×3.514=0.8m ∴ height of the pit =0.8m

Answer 2

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8A.

Given:

A pit of length 6m,breadth 7.5 m and height 4m is dug in the park. What volume of earth is removed ?

To Find:

We should have to Solve this Problem with using Cuboid formula.

∴ Cuboid formula = L × B × H.

(L = Length, B = Breadth and H = Height So, we should write it as 'Length × Breadth × Height).

Solution:

Length of Pit = 6m.

Breadth of Pit = 7.5m.

Height of Pit = 4m.

So, Now Calculate...

⇒ L × B × H

⇒ 6m × 7.5m × 4m.

⇒  = 180m

∴ Therefore, The Answer is 180m.

9A.

Given:

A vegetable seller brought 4370 tomatoes. out of these 242 were found rotten. Remaining tomatoes were packed equally in 43 baskets. Find the no. of tomatoes in each basket?

To Find:

Write total No.of Tomatoes Bought and Subtract Rotten. And Make Cancellation with 43 and Write the Solution of That Rotten and Good Tomatoes.

Solution:

Total No.of Tomatoes Bought = 4370.

No.of Tomatoes Rotten = 242.

⇒ Total - Rotten.

⇒ 4370 - 242.

⇒ 4,128.

No.of Packets = 43.

No.of Tomatoes = 4128/43

= 96.

∴ Therefore, The Number of Tomatoes in each basket = 96.

Hope It'll Helps!