Question

answer for above pic ​

Answer 1

$\sec(50) \times \sin(40 ) + \cos(40) \times \cosec(50)$

$\frac{1}{ \cos(50) } \times \sin(40 ) + \cos(40) \times \frac{1}{ \sin(50) }$

$\frac{ \sin(40) }{ \cos(50) } + \frac{ \cos(40) }{ \sin(50) }$

$\frac{ \sin(90 - 40) }{ \cos(50) } + \frac{ \cos(90 - 40) }{ \sin(50) }$

$\frac{ \ \cos(50) }{ \ \cos(50)} + \frac{ \sin(50) }{ \sin(50) }$

$1 + 1$

$2$

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